document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59535>Question 59535</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a videotape cannot be recorded on for the first 1 1/3 feet, and there is a 180 foot video tape, how much can be recorded on by solving the equation: 180= t + 1 1/3 for t.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #40786 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=40786\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 180= t + 1 1/3 <BR>\n" );
document.write( "180 = t+(4/3)<BR>\n" );
document.write( "t=180-(4/3)<BR>\n" );
document.write( "t=178 2/3<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );