document.write( "Question 651790: This question has two parts. Given a list of 6 students (i.e. Mary, Sue, Anna, Bob, Sam, John) how many different ways can they be arranged in order first to last with no repeats? I figured out that there would be 720 possible arrangements 6*5*4*3*2*1=720 different combinations. But I don't know how to figure out the second part of the question which is, \"What are the number of times Anna will be listed first out of the six names? \n" ); document.write( "
Algebra.Com's Answer #407815 by stanbon(75887)\"\" \"About 
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This question has two parts. Given a list of 6 students (i.e. Mary, Sue, Anna, Bob, Sam, John) how many different ways can they be arranged in order first to last with no repeats? I figured out that there would be 720 possible arrangements 6*5*4*3*2*1=720.
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\n" ); document.write( "\n" ); document.write( "But I don't know how to figure out the second part of the question which is, \"What are the number of times Anna will be listed first out of the six names?
\n" ); document.write( "Ans: 1*5*4*3*2*1 = 5! = 120 times
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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