document.write( "Question 651790: This question has two parts. Given a list of 6 students (i.e. Mary, Sue, Anna, Bob, Sam, John) how many different ways can they be arranged in order first to last with no repeats? I figured out that there would be 720 possible arrangements 6*5*4*3*2*1=720 different combinations. But I don't know how to figure out the second part of the question which is, \"What are the number of times Anna will be listed first out of the six names? \n" ); document.write( "
Algebra.Com's Answer #407813 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! First part is correct.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Second part:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Anna is locked in the first slot. So you have 6-1 = 5 students and 6-1 = 5 slots left.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So there are 5! = 120 ways to do this. \n" ); document.write( " |