document.write( "Question 651642: The ones and hundreds digits of a three-digit number are interchanged and the new number is subtracted from the first number. The difference obtained is three-digit number 59x. Find x. How am I going to find x ?? I tried by using xyz-zyk=59x but i would get decimal number. \n" ); document.write( "
Algebra.Com's Answer #407802 by ankor@dixie-net.com(22740)\"\" \"About 
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The ones and hundreds digits of a three-digit number are interchanged and the
\n" ); document.write( " new number is subtracted from the first number.
\n" ); document.write( " The difference obtained is three-digit number 59x. Find x.
\n" ); document.write( ":
\n" ); document.write( "The equation should be:
\n" ); document.write( "(100x + 10y + z) - (100z + 10y + x) = 590 + x
\n" ); document.write( "Remove the brackets and combine like terms
\n" ); document.write( "100x - x + 10y - 10y - 100z + z = 590 + x
\n" ); document.write( "99x - 99z = 590 + x
\n" ); document.write( "we know that the right side also has to be divisible by 99, (99*6=594)
\n" ); document.write( "x = 4
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