document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=651777>Question 651777</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A deep sea diving bell is being lowered at a consent rate. After 8 minutes, the bell is at a depth of 600 feet. After 40 minutes the bell is at a depth of 1500 feet. What is the average rate of lowering per minute?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #407796 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=407796\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A deep sea diving bell is being lowered at a consent rate. After 8 minutes, the bell is at a depth of 600 feet. After 40 minutes the bell is at a depth of 1500 feet. What is the average rate of lowering per minute? <BR>\n" );
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document.write( "You have 2 points: (8,600) and (40,1500)<BR>\n" );
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document.write( "average rate = slope = (1500-600)/(40-8) = 900/32 = 450/16 = 28.125 ft/min<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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