document.write( "Question 651576: the digits of a three- digit number are three consecutive even integers. The middle digit is the least and the first digit is the greatest. If the number is divided by twice the sum of its digits, the quotient is 423/18. Find the number. pls really need ur help
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Algebra.Com's Answer #407791 by ankor@dixie-net.com(22740)\"\" \"About 
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the digits of a three-digit number are three consecutive even integer
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\n" ); document.write( "The middle digit is the least and the first digit is the greatest.
\n" ); document.write( "Let n = the middle digit
\n" ); document.write( "then
\n" ); document.write( "(n+4) = the greatest
\n" ); document.write( "and
\n" ); document.write( "(n+2) = the next greatest
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\n" ); document.write( "The sum of the three digits:
\n" ); document.write( "n + (n+2) + (n+4) = (3n+6)
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\n" ); document.write( "If the number is divided by twice the sum of its digits, the quotient is 423/18
\n" ); document.write( "\"%28100%28n%2B4%29+%2B+10n+%2B+%28n%2B2%29%29%2F2%283n%2B6%29\" = \"%28100n+%2B+400+%2B+10n+%2B+n+%2B+2%29%2F%286n%2B12%29\" = \"%28111n%2B402%29%2F%286n%2B12%29\" = \"%283%2837n%2B134%29%29%2F%283%282n%2B4%29%29\"
\n" ); document.write( "Cancel 3
\n" ); document.write( "\"%28%2837n%2B134%29%29%2F%28%282n%2B4%29%29\" = \"423%2F18\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "423(2n+4) = 18(37n + 134)
\n" ); document.write( "846n + 1692 = 666n + 2412
\n" ); document.write( "846n - 666n = 2412 - 1692
\n" ); document.write( "180n = 720
\n" ); document.write( "n = 720/180
\n" ); document.write( "n = 4 is the middle digit of the number
\n" ); document.write( "then
\n" ); document.write( "4 + 4 = 8 is the 1st digit
\n" ); document.write( "and
\n" ); document.write( "4 + 2 = 6 is 3rd digit
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\n" ); document.write( "846 is the number
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\n" ); document.write( "Check this; (number over twice the sum of the digits)
\n" ); document.write( "\"846%2F2%2818%29\" = 846/36 reduces to 423/18
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