document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=651725>Question 651725</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist needs 18 liters of a 30% acid solution. How much of a 20% solution should be mixed with a 40% solution to get that (round your answer to the nearest liter)?\r<BR>\n" );
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document.write( "anyone who can show me how to do this great :) i was stuck on it.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #407784 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=407784\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist needs 18 liters of a 30% acid solution. How much of a 20% solution should be mixed with a 40% <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.20x + 0.40(18-x) = 0.30*18<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "20x + 40*18 - 40x = 30*18<BR>\n" );
document.write( "-20x = -10*18<BR>\n" );
document.write( "x = 9 liters (amt. of 20% solution needed)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "18-x = 9 liters (amt. of 40% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==================== </SPAN>\n" );
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