document.write( "Question 651716: How much of a 50% acid solution must be mixed with 50 gallons of a 12% acid solution to obtain a solution that is 40% acid?\r
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Algebra.Com's Answer #407775 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "Correct Set Up is:
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document.write( " 0.5X + 50(0.12)= 0.4(X+50)   ||The amount of 'solution' on both sides must be the same
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document.write( "         X = 140gal of 50% solution needed
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document.write( "and..
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