document.write( "Question 651716: How much of a 50% acid solution must be mixed with 50 gallons of a 12% acid solution to obtain a solution that is 40% acid?\r
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document.write( "I tried to do 0.5X + 50(0.12)= 0.4, but I got a negative answer. \n" );
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Algebra.Com's Answer #407774 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! How much of a 50% acid solution must be mixed with 50 gallons of a 12% acid solution to obtain a solution that is 40% acid? \n" ); document.write( ". \n" ); document.write( "Let x = amount (gallons) of 50% acid added \n" ); document.write( "then \n" ); document.write( ".50x + .12(50) = .40(x+50) \n" ); document.write( ".50x + 6 = .40x+20 \n" ); document.write( ".10x + 6 = 20 \n" ); document.write( ".10x = 14 \n" ); document.write( "x = 14/.10 \n" ); document.write( "x = 140 gallons\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |