document.write( "Question 651690: A piece of wire is shaped to enclose a square with an area of 121 in^2. It is reshaped to enclose a rectangle which has a length of 13 in. What is the area of the triangle? \n" ); document.write( "
Algebra.Com's Answer #407765 by shweta(56)\"\" \"About 
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Wire is shaped to enclose a square with area 121 inch^2
\n" ); document.write( "Let each side of the square be x inches
\n" ); document.write( " Area of square, A = x^2 = 121
\n" ); document.write( " x=sqrt(121)
\n" ); document.write( " x=11
\n" ); document.write( "Length of the wire will be same as the boundary of the square
\n" ); document.write( "Therefore,
\n" ); document.write( "Length of the wire= Perimeter of the square
\n" ); document.write( " = 4* 11
\n" ); document.write( " =44 inches
\n" ); document.write( "Now same wire is reshaped to enclose a rectangle of length 13 inches,so length of the wire will be same as the perimeter of the rectangle
\n" ); document.write( "Therefore, perimeter of rectangle = 44
\n" ); document.write( "Let 'l' be the length and 'b' be breadth of the rectangle
\n" ); document.write( " Perimeter of rectangle= 2*(l+b)=44
\n" ); document.write( " 2*(13+b)=44
\n" ); document.write( " 13+b=44/2
\n" ); document.write( " 13+b=22
\n" ); document.write( " b=22-13
\n" ); document.write( " b=9 inch
\n" ); document.write( "Area of the rectangle= l*b
\n" ); document.write( " 13*9= 117 inch^2
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