document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=651689>Question 651689</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if 3 times a number is increased by 5, the result is the same as when 77 is decreased by 9 times the number. Find the number<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #407763 by </B><A HREF=/tutors/aboutme.mpl?userid=shweta><B>shweta(56)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shweta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=407763\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the number be 'n'<BR>\n" );
document.write( "3 times the number increased by 5= 3*n +5 = say x<BR>\n" );
document.write( "77 decreased by 9 times the number= 77- 9*n = x<BR>\n" );
document.write( "Equating both the equations<BR>\n" );
document.write( " 3n +5 = 77- 9n<BR>\n" );
document.write( " we will bring the term with the variable together<BR>\n" );
document.write( " 3n + 9n= 77-5<BR>\n" );
document.write( " 12n = 72<BR>\n" );
document.write( "  n= 72/12<BR>\n" );
document.write( "  n= 6 </SPAN>\n" );
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