document.write( "Question 651577: how do I solve,
\n" ); document.write( "12x^3-15x^2-18x=? \n" ); document.write( "

Algebra.Com's Answer #407728 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
12x^3-15x^2-18x = 0
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\n" ); document.write( "Factor:
\n" ); document.write( "3x(4x^2 - 5x - 6) = 0
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\n" ); document.write( "3x(4x^2 - 8x+3x - 6) = 0
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\n" ); document.write( "3x(4x(x-2) + 3(x-2)) = 0
\n" ); document.write( "--------
\n" ); document.write( "3x(x-2)(4x+3) = 0
\n" ); document.write( "------
\n" ); document.write( "x = 0 or x = 2 or x = -3/4
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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