document.write( "Question 651569: A and B are supplementary angles. mA is 6° less than twice mB. Find mA and mB. \n" ); document.write( "
Algebra.Com's Answer #407721 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "A and B are supplementary angles. mA is 6° less than twice mB. Find mA and mB.\r
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\n" ); document.write( "\n" ); document.write( "Since the angles are supplementary, then angle B = 180 - A\r
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\n" ); document.write( "\n" ); document.write( "We then have: A = 2(180 - A) - 6\r
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\n" ); document.write( "\n" ); document.write( "A = 360 - 2A - 6\r
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\n" ); document.write( "\n" ); document.write( "A + 2A = 354\r
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\n" ); document.write( "\n" ); document.write( "3A = 354\r
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\n" ); document.write( "\n" ); document.write( "Angle A = \"354%2F3\", or \"highlight_green%28118%5Eo%29\"\r
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\n" ); document.write( "\n" ); document.write( "Angle B = 180 - 118, or \"highlight_green%2862%5Eo%29\"\r
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\n" ); document.write( "\n" ); document.write( "You can do the check!!\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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