document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=651569>Question 651569</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A and B are supplementary angles. mA is 6° less than twice mB. Find mA and mB. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #407718 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=407718\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A and B are supplementary angles. mA is 6° less than twice mB. Find mA and mB.<BR>\n" );
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document.write( "Let mA = 180-x<BR>\n" );
document.write( "Then mB = x<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "180-x = 2x-6<BR>\n" );
document.write( "3x = 186<BR>\n" );
document.write( "x = 31 degrees (measure of B)<BR>\n" );
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document.write( "180-x = 180-31 = 149 degrees (measure of A)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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