document.write( "Question 651360: twice a number increased by 35 is equal to the square of the number \n" ); document.write( "
Algebra.Com's Answer #407621 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "twice a number\"highlight%28x%29\" increased by 35 is equal to the square of the number
\n" ); document.write( "Question states***
\n" ); document.write( " 2x + 35 = x^2
\n" ); document.write( " x^2 - 2x - 35 = 0
\n" ); document.write( "factoring
\n" ); document.write( " (x-7)(x+5) = 0
\n" ); document.write( " (x-7)= 0, x = 7
\n" ); document.write( "0r (x+5) = 0 x = -5
\n" ); document.write( "and..
\n" ); document.write( "\"2%2A7+%2B35+=+7%5E2+=+49\"
\n" ); document.write( " \"2%2A-5+%2B+35+=+%28-5%29%5E2+=++25\" \n" ); document.write( "
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