document.write( "Question 59491: Can someone help me on this problem?\r
\n" );
document.write( "\n" );
document.write( " Given g(x) = 3x + 2,
\n" );
document.write( " I need to find g(4a)\r
\n" );
document.write( "\n" );
document.write( " Thanks allot,
\n" );
document.write( " Ashley \n" );
document.write( "
Algebra.Com's Answer #40761 by tutorcecilia(2152) You can put this solution on YOUR website! g(x) = 3x + 2 \n" ); document.write( "g(x) = 3(4a) + 2 \n" ); document.write( "g(x) = 12a+2 \n" ); document.write( " \n" ); document.write( " |