document.write( "Question 651121: how do i solve the following inequality?\r
\n" ); document.write( "\n" ); document.write( "the absolute value of 7-3y divided by 2 < 1 (the whole fraction is absolute valued)
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Algebra.Com's Answer #407560 by lwsshak3(11628)\"\" \"About 
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absolute value of 7-3y divided by 2 < 1
\n" ); document.write( "|(7-3y)/2|<1
\n" ); document.write( "Solve for 2 conditions:
\n" ); document.write( "(7-3y)/2<1
\n" ); document.write( "multiply both sides by 2
\n" ); document.write( "7-3y<2
\n" ); document.write( "add -7
\n" ); document.write( "-3y<-5
\n" ); document.write( "divide by -3 and reverse inequality sign
\n" ); document.write( "y>5/3
\n" ); document.write( "or
\n" ); document.write( "-(7-3y)/2<1
\n" ); document.write( "multiply both sides by 2
\n" ); document.write( "-7+3y<2
\n" ); document.write( "add 7
\n" ); document.write( "3y<9
\n" ); document.write( "y<3
\n" ); document.write( "number line\r
\n" ); document.write( "\n" ); document.write( "<.......5/3<===>3..........>
\n" ); document.write( "solution: (5/3,3)
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