document.write( "Question 651092: One number is eight less than twice the other their sum is 100 what are the numbers \n" ); document.write( "
Algebra.Com's Answer #407550 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "let's \"x\" and \"y\" be the numbers\r
\n" ); document.write( "\n" ); document.write( "if the number \"x\" is eight less than twice the \"y\", we have \r
\n" ); document.write( "\n" ); document.write( "\"x%2B8=2y\"........1\r
\n" ); document.write( "\n" ); document.write( "if their sum is \"100\",we have\r
\n" ); document.write( "\n" ); document.write( "\"x%2By=100\"...........2\r
\n" ); document.write( "\n" ); document.write( "now, we have to solve this system:\r
\n" ); document.write( "\n" ); document.write( "\"x%2B8=2y\"........1
\n" ); document.write( "-
\n" ); document.write( "\"x%2By=100\"...........2
\n" ); document.write( "______________________ we can subtract 2 from 1\r
\n" ); document.write( "\n" ); document.write( "\"x-x%2B8-y=2y-100\"\r
\n" ); document.write( "\n" ); document.write( "\"cross%28x%29-cross%28x%29%2B8-y=2y-100\"\r
\n" ); document.write( "\n" ); document.write( "\"8-y=2y-100\"\r
\n" ); document.write( "\n" ); document.write( "\"8%2B100=2y%2By\"\r
\n" ); document.write( "\n" ); document.write( "\"108=3y\"\r
\n" ); document.write( "\n" ); document.write( "\"108%2F3=y\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%2836=y%29\"...now find \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2By=100\"...........2\r
\n" ); document.write( "\n" ); document.write( "\"x=100-y\"\r
\n" ); document.write( "\n" ); document.write( "\"x=100-36\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=64%29\"\r
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