document.write( "Question 651023: how would you solve these systems\r
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document.write( "2x-y+z=3
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document.write( "3x-3y-z=4
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document.write( "x+3y+3z=6 \n" );
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Algebra.Com's Answer #407545 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Line them up so that like letters line up vertically, you might\r\n" ); document.write( "like to put 1 coefficients before letters not showing a coefficient:\r\n" ); document.write( "\r\n" ); document.write( "eq.1 2x-1y+1z = 3\r\n" ); document.write( "eq.2 3x-3y-1z = 4\r\n" ); document.write( "eq.3 1x+3y+3z = 6\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "I. Pick a pair of equations and a letter that both contain and \r\n" ); document.write( " eliminate that letter from them.\r\n" ); document.write( "\r\n" ); document.write( "I pick eq.1 and eq.2 and z to eliminate from them:\r\n" ); document.write( "\r\n" ); document.write( "eq.1 2x-1y+1z = 3\r\n" ); document.write( "eq.2 3x-3y-1z = 4\r\n" ); document.write( "\r\n" ); document.write( "The coefficients are z in eq.1 and eq.2 are 1 and -1 which will \r\n" ); document.write( "cancel if we add corresponding terms in the two equations:\r\n" ); document.write( "\r\n" ); document.write( "eq.1 2x-1y+1z = 3\r\n" ); document.write( "eq.2 3x-3y-1z = 4 \r\n" ); document.write( "--------------------\r\n" ); document.write( "eq.4 5x-4y = 7\r\n" ); document.write( "\r\n" ); document.write( "II. Use the equation you haven't used yet with one of the other\r\n" ); document.write( " equations and eliminate that SAME letter from them.\r\n" ); document.write( "\r\n" ); document.write( "We haven't used eq.3 yet, so we put eq.3 with, say eq.2, and we\r\n" ); document.write( "eliminate the same variable that we eliminated in the first step: \r\n" ); document.write( "\r\n" ); document.write( "eq.2 3x-3y-1z = 4\r\n" ); document.write( "eq.3 1x+3y+3z = 6\r\n" ); document.write( "\r\n" ); document.write( "[Caution: Even though the y's would cancel if we added them just\r\n" ); document.write( "as they are, DO NOT add them, because we must eliminate the SAME \r\n" ); document.write( "letter we eliminated before, which is z, not y.]\r\n" ); document.write( "\r\n" ); document.write( "To eliminate z we must multiply both sides of eq.2 by 3 to make\r\n" ); document.write( "the -1z term, become -3z, and then add them\r\n" ); document.write( "\r\n" ); document.write( " 9x-9y-3z = 12\r\n" ); document.write( "eq.3 1x+3y+3z = 6\r\n" ); document.write( " -------------\r\n" ); document.write( " 10x-6y = 18\r\n" ); document.write( "\r\n" ); document.write( "That can be divided through by 2, so we will do that:\r\n" ); document.write( "\r\n" ); document.write( "eq.5 5x-3y = 9\r\n" ); document.write( "\r\n" ); document.write( "III. Solve the resulting 2×2 system of equations:\r\n" ); document.write( "\r\n" ); document.write( "So we put eq.5 with eq.4:\r\n" ); document.write( "\r\n" ); document.write( "eq.4 5x-4y = 7\r\n" ); document.write( "eq.5 5x-3y = 9\r\n" ); document.write( "\r\n" ); document.write( "The 5x in eq.4 can be made to cancel the 5x in eq.5 by\r\n" ); document.write( "multiplying eq.4 by -1\r\n" ); document.write( "\r\n" ); document.write( " -5x+4y = -7\r\n" ); document.write( "eq.5 5x-3y = 9\r\n" ); document.write( " -----------\r\n" ); document.write( " y = 2\r\n" ); document.write( " \r\n" ); document.write( "Now we substitute in either eq.4 or eq.5 to find x. Say,\r\n" ); document.write( "pick eq.5 and substitute y = 2\r\n" ); document.write( "\r\n" ); document.write( "eq.5 5x-3y = 9\r\n" ); document.write( " 5x-3(2) = 9\r\n" ); document.write( " 5x-6 = 9\r\n" ); document.write( " 5x = 15\r\n" ); document.write( " x = 3\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "IV. Substitute the values obtained into one of the original equations\r\n" ); document.write( " to find the remaining variable, which was the firet ofne eliminated.\r\n" ); document.write( "\r\n" ); document.write( "So we substitute x = 4 and y = 2 in any of the original 3 equations \r\n" ); document.write( "to find z, which was the first letter we eliminated. I'll use eq.1:\r\n" ); document.write( "\r\n" ); document.write( "eq.1 2x-1y+1z = 3\r\n" ); document.write( " 2(3)-1(2)+1z = 3\r\n" ); document.write( " 6-2+z = 3\r\n" ); document.write( " 4+z = 3\r\n" ); document.write( " z = -1\r\n" ); document.write( "\r\n" ); document.write( "Solution (x,y,z) = (4,2,-1)\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |