document.write( "Question 651004:
\n" ); document.write( "A certain metal is 40% copper. How many kilograms of this metal must be mixed with 60 kilograms of a metal that is 70% copper to get a metal that is 50% copper?
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Algebra.Com's Answer #407525 by josmiceli(19441)\"\" \"About 
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Let \"+x+\" = kg of 40% metal needed
\n" ); document.write( "\"+.4x+\" = kg of copper in 40% metal
\n" ); document.write( "\"+.7%2A60+=+42+\" kg of copper in 70% metal
\n" ); document.write( "\"+%28+.4x+%2B+42+%29+%2F+%28+x+%2B+60+%29+=+.5+\"
\n" ); document.write( "\"+.4x+%2B+42+=+.5%2A%28+x+%2B+60+%29+\"
\n" ); document.write( "\"+.4x+%2B+42+=+.5x+%2B+30+\"
\n" ); document.write( "\"+.1x+=+12+\"
\n" ); document.write( "\"+x+=+120+\"
\n" ); document.write( "120 kg of the 40% metal are needed
\n" ); document.write( "check:
\n" ); document.write( "\"+%28+.4%2A120+%2B+42+%29+%2F+%28+120+%2B+60+%29+=+.5+\"
\n" ); document.write( "\"+%28+48+%2B+42+%29+%2F+180+=+.5+\"
\n" ); document.write( "\"+90%2F180+=+.5+\"
\n" ); document.write( "\"+90+=+.5%2A180+\"
\n" ); document.write( "\"+90+=+90+\"
\n" ); document.write( "OK\r
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