document.write( "Question 650978: hi,im a student 15 years old, having trouble with finding the solution to this question.\r
\n" ); document.write( "\n" ); document.write( "6x + 5y = 7 & x - y = 3 \r
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\n" ); document.write( "\n" ); document.write( "i have to find the coordinates (x,y) i found that the answer is x= 2 and y = -1
\n" ); document.write( "but i dont know how to find the soulution. Please help thanks.
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Algebra.Com's Answer #407519 by nerdybill(7384)\"\" \"About 
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6x + 5y = 7 & x - y = 3
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\n" ); document.write( "apply the \"substitution method\", solve the right equation for x:
\n" ); document.write( "x - y = 3
\n" ); document.write( "x = y+3
\n" ); document.write( "substitute above into the left equation to find y:
\n" ); document.write( "6x + 5y = 7
\n" ); document.write( "6(y+3) + 5y = 7
\n" ); document.write( "6y+18 + 5y = 7
\n" ); document.write( "11y+18 = 7
\n" ); document.write( "11y = -11
\n" ); document.write( "y = -1
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\n" ); document.write( "substitute above into the right equation to find x:
\n" ); document.write( "x - y = 3
\n" ); document.write( "x - (-1) = 3
\n" ); document.write( "x + 1 = 3
\n" ); document.write( "x = 2
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\n" ); document.write( "solution: (x,y) = (2, -1)
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