document.write( "Question 650884: Please help me find the value of x!\r
\n" ); document.write( "\n" ); document.write( "(2)^3x = (16)^x+2
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Algebra.Com's Answer #407480 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Hint:\r
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\n" ); document.write( "\n" ); document.write( "(2)^3x = (16)^x+2\r
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\n" ); document.write( "\n" ); document.write( "(2)^3x = (2^4)^x+2\r
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\n" ); document.write( "\n" ); document.write( "(2)^3x = 2^(4(x+2)\r
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\n" ); document.write( "\n" ); document.write( "Since the bases are equal (to 2), the exponents must be equal, so..\r
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\n" ); document.write( "\n" ); document.write( "3x = 4(x+2)\r
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\n" ); document.write( "\n" ); document.write( "I'll let you finish\r
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\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
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