document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=650797>Question 650797</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Water is pouring into an inverted cone at the rate of 3.14 cubic meters per minute. The height of the cone is 10 meters, and the radius of its base is 5 meters. How fast is the water level rising when the water stands 7.5 meters above the base? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #407411 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=407411\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Water is pouring into an inverted cone at the rate of 3.14 cubic meters per minute. The height of the cone is 10 meters, and the radius of its base is 5 meters. How fast is the water level rising when the water stands 7.5 meters above the base?<BR>\n" );
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document.write( " \"when the water stands 7.5 meters above the base\"  implies the point is at the top, not inverted.  r = h/2 if h is measured from the point of the cone.<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V+=+pi%2Ar%5E2h%2F3 ALIGN=MIDDLE  ALT=\"V+=+pi%2Ar%5E2h%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "r = h/2<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V+=+pi%2Ah%5E3%2F12 ALIGN=MIDDLE  ALT=\"V+=+pi%2Ah%5E3%2F12\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=dV%2Fdt+=+3pih%5E2%2F4%2A%28dh%2Fdt%29 ALIGN=MIDDLE  ALT=\"dV%2Fdt+=+3pih%5E2%2F4%2A%28dh%2Fdt%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 3.14 m^3/min<BR>\n" );
document.write( "Using the 3.14 for pi<BR>\n" );
document.write( "dh/dt = 4/(3h^2) m/min<BR>\n" );
document.write( "dh/dt = 4/(3*56.25) = 0.0237 meter/minute<BR>\n" );
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