document.write( "Question 650800: x^3+125=0 \n" ); document.write( "
Algebra.Com's Answer #407407 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi,
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document.write( "x^3+125=0
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document.write( " x^3 = -125
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document.write( "\"x+=+root%283%2C-125%29\"
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document.write( "    x = -5\r
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document.write( "and \"-5%2A-5%2A-5+=+-125\" \n" );
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