document.write( "Question 650759: ((x^2(1+x^2)^(1/2))-(x^2(1+x^2)^(-1/2)))/(1+x^2)
\n" ); document.write( "What is the domain of the question above? and also would you be kind enough to show me the steps?
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Algebra.Com's Answer #407392 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "To find the domain, I'll ignore the \"\" in the numerator (since the numerator \"does\" \"not\" \r
\n" ); document.write( "\n" ); document.write( "cause division by \"zero\") and instead I'll look at the \"denominator\" \r
\n" ); document.write( "\n" ); document.write( "\"1%2Bx%5E2\". \r
\n" ); document.write( "\n" ); document.write( "I'll set the denominator equal to \"zero\", and solve. \r
\n" ); document.write( "\n" ); document.write( "\"1%2Bx%5E2=0\"\r
\n" ); document.write( "\n" ); document.write( "The \"x-values\" in the solution will be the \"x-values\" which would cause \r
\n" ); document.write( "\n" ); document.write( "division by \"zero\". The domain will then be all other \"x-values\".\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2=-1\"\r
\n" ); document.write( "\n" ); document.write( "\"x=sqrt%28-1%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=i\" and \"x=-i\"\r
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\n" ); document.write( "\n" ); document.write( "...as you can see here, whatever \"x\" is, the denominator will NOT be equal \r
\n" ); document.write( "\n" ); document.write( "to \"zero\"\r
\n" ); document.write( "\n" ); document.write( "so, the domain will be all real numbers from \"-infinity\" to \"infinity\"\r
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\n" ); document.write( "\n" ); document.write( "(\"-infinity\" ,\"infinity\")\r
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