document.write( "Question 650706: A=2(pi)(a)^2 solve for a. Sorry I didn't know what column to put this under. I keep getting square root of A/2(pi)=a?? \n" ); document.write( "
Algebra.Com's Answer #407377 by MathTherapy(10556)\"\" \"About 
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A=2(pi)(a)^2 solve for a. Sorry I didn't know what column to put this under. I keep getting square root of A/2(pi)=a??\r
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\n" ); document.write( "\n" ); document.write( "That's partially correct!! The denominator needs to be rationalized!!\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+2%2Api%2Aa%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"A%2F%282%2Api%29+=+a%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"_%2B-sqrt%28A%2F%282%2Api%29%29+=+sqrt%28a%5E2%29\" ------ Taking square root of each side of equation\r
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\n" ); document.write( "\n" ); document.write( "\"_%2B-+%28sqrt%28A%29%29%2Fsqrt%282%2Api%29+=+a\"\r
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\n" ); document.write( "\n" ); document.write( " ---- Rationalizing denominator\r
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\n" ); document.write( "\n" ); document.write( "\"_%2B-+%28sqrt%28A+%2A+2+%2A+pi%29%29%2F%28sqrt%282%2Api%2A2%2Api%29%29+=+a\"\r
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\n" ); document.write( "\n" ); document.write( "\"_%2B-+%28sqrt%282A+%2A+pi%29%29%2F%28sqrt%282%5E2%2Api%5E2%29%29+=+a\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight_green%28_%2B-+%28sqrt%282A+%2A+pi%29%29%2F%282+%2A+pi%29+=+a%29\"\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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