document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=650507>Question 650507</A>: <I><SPAN STYLE=\"word-break: break-all;\"> angle a and angle b are supplementary. Twice the measure of angle a is one-half the measure of angle b. find the angle of measure b </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #407328 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=407328\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> angle a and angle b are supplementary. Twice the measure of angle a is one-half the measure of angle b. find the angle of measure b<BR>\n" );
document.write( "**<BR>\n" );
document.write( "a+b=180º<BR>\n" );
document.write( "a=180-b<BR>\n" );
document.write( "..<BR>\n" );
document.write( "2a=b/2<BR>\n" );
document.write( "2(180-b)=b/2<BR>\n" );
document.write( "360 -2b=b/2  <BR>\n" );
document.write( "720-4b=b<BR>\n" );
document.write( "5b=720<BR>\n" );
document.write( "b=144         <BR>\n" );
document.write( "angle of measure b=144º </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );