document.write( "Question 650299: Hi, \r
\n" ); document.write( "\n" ); document.write( "I am just beginning Precalculus, and am confused about the process that involves solving for theta where there are actually two answers. I kind of understand the concept (the angle and its inverse, somehow) but do not know how to actually reach the two answers.\r
\n" ); document.write( "\n" ); document.write( "The problem I am looking at is cos (θ) = -√(3)/2\r
\n" ); document.write( "\n" ); document.write( "I have tried several methods that end in bizarre answers. Any help would be appreciated, thank you.\r
\n" ); document.write( "\n" ); document.write( "-Alex
\n" ); document.write( "

Algebra.Com's Answer #407291 by MathTherapy(10555)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi, \r
\n" ); document.write( "\n" ); document.write( "I am just beginning Precalculus, and am confused about the process that involves solving for theta where there are actually two answers. I kind of understand the concept (the angle and its inverse, somehow) but do not know how to actually reach the two answers.\r
\n" ); document.write( "\n" ); document.write( "The problem I am looking at is cos (θ) = -√(3)/2\r
\n" ); document.write( "\n" ); document.write( "I have tried several methods that end in bizarre answers. Any help would be appreciated, thank you.\r
\n" ); document.write( "\n" ); document.write( "-Alex\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "cos (θ) = \"-+%28sqrt%283%29%29%2F2\" ----- \"cos%5E-1%28%28-+sqrt%283%29%29%2F2%29\" = \"-30%5Eo\"\r
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\n" ); document.write( "\n" ); document.write( "As the angle is cos and < 0, \"cos%28-+30%29\" is in the 2nd quadrant, where its reference angle = \"highlight_green%28150%5Eo%29\", and in the 3rd quadrant where its reference angle = \"highlight_green%28210%5Eo%29\"\r
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\n" ); document.write( "\n" ); document.write( "OR\r
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\n" ); document.write( "\n" ); document.write( "You could also look at the unit circle and see that:\r
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\n" ); document.write( "\n" ); document.write( "\"cos%28%28-+sqrt%283%29%29%2F2%29\" = \"150%5Eo\" and \"210%5Eo\" in the 2nd and 3rd quadrants, respectively.\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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