document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59426>Question 59426</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you show me how to solve this problem please?<BR>\n" );
document.write( "8(2x-9)-3=8(x-8)+(5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #40726 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=40726\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8(2x-9) - 3 = 8(x-8) + 5<BR>\n" );
document.write( "First we remove the parenthesis by multiplying the terms inside the parenthesis and the outside factor.\r<BR>\n" );
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document.write( "==> 16x - 72 - 3 = 8x - 64 + 5\r<BR>\n" );
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document.write( "==> 16x - 75 = 8x - 59  [simplifying the values]\r<BR>\n" );
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document.write( "==> 16x - 8x = -59 + 75  [Adding 75-8x to both the sides ]\r<BR>\n" );
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document.write( "==>  8x = 16 [simplifying the like terms]\r<BR>\n" );
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document.write( "==>  8x/8 = 16/8\r<BR>\n" );
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document.write( "==>x = 2\r<BR>\n" );
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document.write( "Good Luck!!!  </SPAN>\n" );
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