document.write( "Question 650165: a perimeter of a rectangle is 78 feet. its length is seven feet more than its width. what are the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #407207 by sachi(548)![]() ![]() You can put this solution on YOUR website! let the width is w \n" ); document.write( "then length is w+7 \n" ); document.write( "so perimeter=2(w+7+w)=78 \n" ); document.write( "or 2w+7=78/2=39 \n" ); document.write( "or 2w=39-7=32 \n" ); document.write( "or w=32/2=16 & l=16+7=23 \n" ); document.write( "ans \n" ); document.write( " |