document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59422>Question 59422</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0918091705/algebrahomeworkh>college algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> what is the answer to msquare+4m-21\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #40719 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=40719\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> m^2 + 4m - 21<BR>\n" );
document.write( "I believe you need to factor this<BR>\n" );
document.write( "= m^2 + 7m - 3m - 21 [Splitting the middle term 4m as 7m - 3m so that 7*3 = 21]<BR>\n" );
document.write( "= m( m+7) - 3(m + 7)  [Taking the common factor from the first and the last   \r<BR>\n" );
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document.write( "                        two terms]\r<BR>\n" );
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document.write( "= (m+7) (m - 3) [Again (m+7) is a common factor taken out]\r<BR>\n" );
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document.write( "m^2 + 4m - 21 = (m+7)(m-3)\r<BR>\n" );
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document.write( "Good Luck!!!<BR>\n" );
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