document.write( "Question 59388This question is from textbook
\n" ); document.write( ": Science and medicine. Martina leaves home at 9 A.M., bicycling at a rate of
\n" ); document.write( "24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time
\n" ); document.write( "will John catch up with Martina?
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Algebra.Com's Answer #40718 by funmath(2933)\"\" \"About 
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Science and medicine. Martina leaves home at 9 A.M., bicycling at a rate of
\n" ); document.write( "24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina?
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\n" ); document.write( "The distance formula is:\"highlight%28d=rt%29\", d=distance, r=rate, and t=time.
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\n" ); document.write( "Martina's r=24 mi/h
\n" ); document.write( "Let Martina's time be: t (we don't know what it is)
\n" ); document.write( "Then Martina's distance d=24t
\n" ); document.write( ":
\n" ); document.write( "John's r=48 mi/h
\n" ); document.write( "John left two hours later so he traveled 2 hours less than Martina: t-2
\n" ); document.write( "Then John's distance d=48(t-2)
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\n" ); document.write( "John Catches up to Martina, so their distances are equal.
\n" ); document.write( "Problem to solve:
\n" ); document.write( "24t=48(t-2)
\n" ); document.write( "24t=48t-96
\n" ); document.write( "-48t+24t=-48t+48t-96
\n" ); document.write( "-24t=-96
\n" ); document.write( "-24t/-24=-96/-24
\n" ); document.write( "t=4
\n" ); document.write( "That means that Martina traveled for 4 hours.
\n" ); document.write( "She left at 9am, four hours later makes it 1pm.
\n" ); document.write( "Happy Calculating!!!
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