document.write( "Question 650112: Explain and demonstrate how to factor a trinomial in the form: ax^2+bx+c with an example where a, b and c are values \n" ); document.write( "
Algebra.Com's Answer #407167 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "what you are looking for is called \"expansion\" and \"grouping\" \r
\n" ); document.write( "\n" ); document.write( "so, you have to to expand \"\"bx\"\" into \"two\" terms, such that one term will have a \"common\" \"factor\" with \"a\" and the other will have a \"common\" \"factor\" with \"c\"\r
\n" ); document.write( "\n" ); document.write( "for example:\r
\n" ); document.write( "\n" ); document.write( "\"2x%5E2+-+x+-+3\"\r
\n" ); document.write( "\n" ); document.write( "you are going find numbers that are factors of \"-6\" (these are \"2+%2A+-3\") ) that \"add\" \"up\" to \"-1\" (\"-x+=+-1x\")
\n" ); document.write( "these factors are \"-3\" and \"2\"\r
\n" ); document.write( "\n" ); document.write( "so you would rewrite the equation as:\r
\n" ); document.write( "\n" ); document.write( "\"2x%5E2+%2B+2x+-+3x+-+3\" (doing so,you didn't really change anything, because \"2+-+3+=+-1\", so the integrity of the expression is still there)\r
\n" ); document.write( "\n" ); document.write( "now you factor in parts. from the first part, take out \"2x\", from the second, take out \"-3\"\r
\n" ); document.write( "\n" ); document.write( "so, you have:\r
\n" ); document.write( "\n" ); document.write( "\"2x%28x+%2B+1%29+-+3%28x+%2B+1%29\" . . . . (if you notice, both of the terms in the ()'s are the same, this will always happen if it doesn't, you have done something wrong\r
\n" ); document.write( "\n" ); document.write( "then you say:\r
\n" ); document.write( "\n" ); document.write( "\"%282x+-+3%29%28x+%2B+1%29\"...that's factored \r
\n" ); document.write( "\n" ); document.write( "if u multiply this out, you will get back to the original expression of \"2x%5E2+-+x+-+3\"
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