document.write( "Question 650070: When each side of a given square is increased by 4 feet the are is increased by 64 square feet. Determine the dimensions of the original square. \n" ); document.write( "
Algebra.Com's Answer #407156 by shweta(56)\"\" \"About 
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Let the side of a square be 's'feet
\n" ); document.write( "Area of the square= s*s=s^2 feet
\n" ); document.write( "Now side increases by 4 feet, s+ 4
\n" ); document.write( "The area also increases by 64 feet
\n" ); document.write( "We get,
\n" ); document.write( " (s+4)^2= s^2 + 64 ...(1)
\n" ); document.write( " Apply the formula (a+b)^2= a^2 +b^2+ 2*a*b
\n" ); document.write( " s^2 + 4^2+ 2*s*4= s^2+ 64
\n" ); document.write( "s^2 on both the sides get cancelled
\n" ); document.write( " 4^2+ 8s= 64
\n" ); document.write( " 16+ 8s= 64
\n" ); document.write( " We have to shift the variable on one side and the numbers on the other side of 'equal to'sign
\n" ); document.write( " 8s= 64- 16
\n" ); document.write( " 8s= 48
\n" ); document.write( " s= 48/8 ( here 48 is divided by 8 because on the other side of 'equal to' sign 8 was multiplied to s)
\n" ); document.write( " s=6
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