document.write( "Question 649546: REDUCING THE SIZE OF A CANDY BAR \r
\n" ); document.write( "\n" ); document.write( "a jumbo chocolate bar with a rectangular shape measures 12 centimeters in length, 7 centimeters in width, and 3 centimeters in thickness. Due to escalating costs in cocoa, management decides to reduce the volume of the bar by 20%. too accomplish this reduction, management decides that the new bar should have the same 3 centimeters in thickness, but the length and width of each should be reduced an equal number of centimeters. what should be the dimensions of the new candy bar?\r
\n" ); document.write( "\n" ); document.write( "i know that volume=LWH which would then be v=(12)(7)(3) so v=252 cm^3 and then i would multiply by 20% to get 50.4 cm^3 then subtract to get 201.6 cm^3 \r
\n" ); document.write( "\n" ); document.write( "then i would set that as 201.6 cm^3 = (3)(L)(W) divide each side by 3 to get 67.2 cm^3=(L)(W)
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\n" ); document.write( "Thats where I get stuck... Thanks!
\n" ); document.write( "

Algebra.Com's Answer #407152 by MathTherapy(10556)\"\" \"About 
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\n" ); document.write( "REDUCING THE SIZE OF A CANDY BAR \r
\n" ); document.write( "\n" ); document.write( "a jumbo chocolate bar with a rectangular shape measures 12 centimeters in length, 7 centimeters in width, and 3 centimeters in thickness. Due to escalating costs in cocoa, management decides to reduce the volume of the bar by 20%. too accomplish this reduction, management decides that the new bar should have the same 3 centimeters in thickness, but the length and width of each should be reduced an equal number of centimeters. what should be the dimensions of the new candy bar?\r
\n" ); document.write( "\n" ); document.write( "i know that volume=LWH which would then be v=(12)(7)(3) so v=252 cm^3 and then i would multiply by 20% to get 50.4 cm^3 then subtract to get 201.6 cm^3 \r
\n" ); document.write( "\n" ); document.write( "then i would set that as 201.6 cm^3 = (3)(L)(W) divide each side by 3 to get 67.2 cm^3=(L)(W)
\n" ); document.write( "
\n" ); document.write( "Thats where I get stuck... Thanks! \r
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\n" ); document.write( "\n" ); document.write( "Volume of candy bar before reduction = 12 * 7 * 3, or 252 \"cm%5E2\"
\n" ); document.write( "Reduction by 20% results in a reduced candy bar volume of: .8(252), or 201.6 \"cm%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Let length of reduced bar be L
\n" ); document.write( "Then width = L also
\n" ); document.write( "Since volume of reduced bar = 201.6, and with thickness being the same (3 cm), then we have: L(L)(3) = 201.6
\n" ); document.write( "\"3L%5E2+=+201.6\"
\n" ); document.write( "\"3%28L%5E2%29+=+3%2867.2%29\"
\n" ); document.write( "\"L%5E2+=+67.2\" ---- This is where you got stuck, but it should be L * L, since L = W
\n" ); document.write( "\"L+=+sqrt%2867.2%29\"\r
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\n" ); document.write( "\n" ); document.write( "L, or length of reduced bar = = 8.2 (rounded). Width = 8.2 (rounded) also.\r
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\n" ); document.write( "\n" ); document.write( "Dimensions of new candy bar = \"highlight_green%28%288.2%29+by+%288.2%29+by+%283%29%29\" \"cm%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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