document.write( "Question 59411: A clerk was asked to change a $10 bill. She returned 9 more dimes than nickels and 21 more quarters than dimes. How many of coins of each did she return?\r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #40715 by uma(370) ![]() You can put this solution on YOUR website! Let x be the number of nickels the clerk returned. \n" ); document.write( "So number of dimes brought = x + 9 \n" ); document.write( "Number of quarters retuned = (x+9) + 21 \n" ); document.write( " = x + 30\r \n" ); document.write( "\n" ); document.write( "Value of x nickels = 5x cents \n" ); document.write( "Value of (x + 9) dimes = 10(x+9) \n" ); document.write( " = 10x + 90 cents\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Value of (x + 30) quarters = 25(x + 30) \n" ); document.write( " = 25x + 750 cents \n" ); document.write( "Total value = 1000cents\r \n" ); document.write( "\n" ); document.write( "==> 5x + 10x + 90 + 25x + 750 = 1000 \n" ); document.write( "==> 40x + 840 = 1000 \n" ); document.write( "==> 40x = 160 [subtracting 840 from both the sides] \n" ); document.write( "==> x = 4 [dividing by 40 on both the sides]\r \n" ); document.write( "\n" ); document.write( "Number of nickels = 4 \n" ); document.write( "Number of dimes = 4 + 9 = 13 \n" ); document.write( "Number of quarters = 4 + 30 = 34 \n" ); document.write( " |