document.write( "Question 59411: A clerk was asked to change a $10 bill. She returned 9 more dimes than nickels and 21 more quarters than dimes. How many of coins of each did she return?\r
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Algebra.Com's Answer #40715 by uma(370)\"\" \"About 
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Let x be the number of nickels the clerk returned.
\n" ); document.write( "So number of dimes brought = x + 9
\n" ); document.write( "Number of quarters retuned = (x+9) + 21
\n" ); document.write( " = x + 30\r
\n" ); document.write( "\n" ); document.write( "Value of x nickels = 5x cents
\n" ); document.write( "Value of (x + 9) dimes = 10(x+9)
\n" ); document.write( " = 10x + 90 cents\r
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\n" ); document.write( "\n" ); document.write( "Value of (x + 30) quarters = 25(x + 30)
\n" ); document.write( " = 25x + 750 cents
\n" ); document.write( "Total value = 1000cents\r
\n" ); document.write( "\n" ); document.write( "==> 5x + 10x + 90 + 25x + 750 = 1000
\n" ); document.write( "==> 40x + 840 = 1000
\n" ); document.write( "==> 40x = 160 [subtracting 840 from both the sides]
\n" ); document.write( "==> x = 4 [dividing by 40 on both the sides]\r
\n" ); document.write( "\n" ); document.write( "Number of nickels = 4
\n" ); document.write( "Number of dimes = 4 + 9 = 13
\n" ); document.write( "Number of quarters = 4 + 30 = 34
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