document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=650054>Question 650054</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sandro invested Php38,000 in the International Bank of the Philippines at 5% interest. How much additional money must he invest at 10% so that the annual income would be equal to 7.5% of his investment? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #407145 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=407145\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Sandro invested Php38,000 in the International Bank of the Philippines at 5% interest. How much additional money must he invest at 10% so that the annual income would be equal to 7.5% of his investment?<BR>\n" );
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document.write( "let x=additional money invested at 10%<BR>\n" );
document.write( "..<BR>\n" );
document.write( "5%(38000)+10%x=7.5%(38000+x)<BR>\n" );
document.write( "1900+0.10x=2850+.075x<BR>\n" );
document.write( ".10x-.075x=2850-1900<BR>\n" );
document.write( ".025x=950<BR>\n" );
document.write( "x=38000<BR>\n" );
document.write( "additional money invested at 10%=Php38,000 </SPAN>\n" );
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