document.write( "Question 650014: Burt's Burger Barn sold 495 hamburgers today. The number sold with cheese was half the number sold without cheese. How much of each kind were sold?
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document.write( "Can you please explain how to do this as well, I am confused on it \n" );
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Algebra.Com's Answer #407142 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Burt's Burger Barn sold 495 hamburgers today. The number sold with cheese was half the number sold without cheese. How much of each kind were sold? \n" ); document.write( "Can you please explain how to do this as well, I am confused on it\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let amount of cheeseburgers sold be C\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then amount of burgers sold without cheese = 495 - C, since a total of 495 were sold\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2C = 495 - C ----- Multiplying by LCD, 2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2C + C = 495\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3C = 495\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "C, or amount of cheeseburgers sold = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Amount of burgers without cheese that were sold = 495 - 165, or \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com \n" ); document.write( " |