document.write( "Question 650014: Burt's Burger Barn sold 495 hamburgers today. The number sold with cheese was half the number sold without cheese. How much of each kind were sold?
\n" ); document.write( "Can you please explain how to do this as well, I am confused on it
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Algebra.Com's Answer #407142 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Burt's Burger Barn sold 495 hamburgers today. The number sold with cheese was half the number sold without cheese. How much of each kind were sold?
\n" ); document.write( "Can you please explain how to do this as well, I am confused on it\r
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\n" ); document.write( "\n" ); document.write( "Let amount of cheeseburgers sold be C\r
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\n" ); document.write( "\n" ); document.write( "Then amount of burgers sold without cheese = 495 - C, since a total of 495 were sold\r
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\n" ); document.write( "\n" ); document.write( "Also, \"C+=+%281%2F2%29+%28495+-+C%29\", since the amount sold with cheese was \"1%2F2\" of the amount sold without cheese\r
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\n" ); document.write( "\n" ); document.write( "\"C+=+%28495+-+C%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "2C = 495 - C ----- Multiplying by LCD, 2\r
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\n" ); document.write( "\n" ); document.write( "2C + C = 495\r
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\n" ); document.write( "\n" ); document.write( "3C = 495\r
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\n" ); document.write( "\n" ); document.write( "C, or amount of cheeseburgers sold = \"495%2F3\", or \"highlight_green%28165%29\"\r
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\n" ); document.write( "\n" ); document.write( "Amount of burgers without cheese that were sold = 495 - 165, or \"highlight_green%28330%29\"\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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