document.write( "Question 59411: A clerk was asked to change a $10 bill. She returned 9 more dimes than nickels and 21 more quarters than dimes. How many of coins of each did she return?\r
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Algebra.Com's Answer #40714 by funmath(2933) ![]() You can put this solution on YOUR website! A clerk was asked to change a $10 bill. She returned 9 more dimes than nickels and 21 more quarters than dimes. How many of coins of each did she return? \n" ); document.write( ": \n" ); document.write( "We can avoid decimals if we do this in terms of cents instead of dollars: \n" ); document.write( ": \n" ); document.write( "Let the amount of nickels be: x \n" ); document.write( "Then the amount of money in nickles is: 5x in cents \n" ); document.write( ": \n" ); document.write( "The amount of dime is 9 more than nickles: x+9 \n" ); document.write( "Then the amount of money in dimes is: 10(x+9) in cents \n" ); document.write( ": \n" ); document.write( "The amount of quarters is 21 more than dimes: (x+9)+21=x+30 \n" ); document.write( "Then the amount of money in quarters is: 25(x+30) in cents \n" ); document.write( ": \n" ); document.write( "She has a total of: $10.00 or 1000 in cents \n" ); document.write( "So add all the amounts to = 1000 \n" ); document.write( "Problem to solve: \n" ); document.write( "5x+10(x+9)+25(x+30)=1000 \n" ); document.write( "5x+10x+90+25x+750=1000 \n" ); document.write( "40x+840=1000 \n" ); document.write( "40x+840-840=1000-840 \n" ); document.write( "40x=160 \n" ); document.write( "40x/40=160/40 \n" ); document.write( "x=4 \n" ); document.write( "The amount of nickels: x=4 \n" ); document.write( "The amount of dimes: x+9=4+9=13 \n" ); document.write( "The amount of quarters: x+30=4+30=34 \n" ); document.write( ": \n" ); document.write( "To check add 4 nickels, 13 dimes and 34 quarters and see if you get $10. \n" ); document.write( "$.05(4)+$.10(13)+$.25(34)=$10.00 ? \n" ); document.write( "$.20+$1.30+$8.50=$10.00 ? \n" ); document.write( "$10.00=$10.00 !!! Yeah!!! \n" ); document.write( "Happy Calculating!!! \n" ); document.write( " |