document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59409>Question 59409</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What are some easy steps in solving 2 equations with 2 variables by canceling out one variable while adding both equations together? Apparently when you get your answer, it is suppose to be (x,y) form and nothing else. I am just so confused because the curriculum I have for homeschooling doesn't explain it very well. So, I am in need of some assistance if you can help! I hope I explained my delemma to where you understand it. Thank you...I hope I hear from you soon!\r<BR>\n" );
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document.write( "                                Thanks a bunch!<BR>\n" );
document.write( "                                   Stephanie  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #40708 by </B><A HREF=/tutors/aboutme.mpl?userid=funmath><B>funmath(2933)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=funmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=40708\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here's an example of a problem that I solved for another student, I explained the steps.  I hope that makes things clearer.<BR>\n" );
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document.write( "Solve the following systems by addition. If a unique solution does not exist, I need to state whether the system is inconsistent or dependent.<BR>\n" );
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document.write( "L1) 2x + 3y = 1<BR>\n" );
document.write( "L2) 5x + 3y = 16<BR>\n" );
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document.write( "Multiply L2 by -1 and add it to L2 and the y's will be eliminated.<BR>\n" );
document.write( "-1(5x+3y)=-1(16) --->> -5x-3y=-16<BR>\n" );
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document.write( "2x +3y=1<BR>\n" );
document.write( "-5x-3y=-16<BR>\n" );
document.write( "____________<BR>\n" );
document.write( "-3x+0y=-15<BR>\n" );
document.write( "-3x=-15<BR>\n" );
document.write( "-3x/-3=-15/-3<BR>\n" );
document.write( "x=5<BR>\n" );
document.write( "Substitute x=5 into L1 and solve for y:<BR>\n" );
document.write( "2(5)+3y=1<BR>\n" );
document.write( "10+3y=1<BR>\n" );
document.write( "-10+10+3y=1-10<BR>\n" );
document.write( "3y=-9<BR>\n" );
document.write( "3y/3=-9/3<BR>\n" );
document.write( "y=-3<BR>\n" );
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document.write( "The solution is (x,y)=(5,-3)<BR>\n" );
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document.write( "FYI, if you go to eliminate one variable and both variables get eliminated and you get two numbers that aren't equal like 4=5, then the system has no solution and is inconsistent. If the same thing happens, but the numbers left do equal each other like 4=4, then the system has an infinite number of solutions and the system is dependent.<BR>\n" );
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document.write( "Happy Calculating!!! </SPAN>\n" );
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