document.write( "Question 59407: Please find derivative and simplify:\r
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document.write( "y= x^3ln3x\r
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document.write( "y= e^ln5x\r
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document.write( "y= e^lnx\r
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document.write( "y= ln(5x+2)^3/ln(5x+2)\r
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document.write( "i've completed over half of my homework, but i'm stuck right here...please help \n" );
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Algebra.Com's Answer #40704 by uma(370) ![]() You can put this solution on YOUR website! (i) y = x^3 ln3x \n" ); document.write( "This is a product and we apply product rule. \n" ); document.write( "dy/dx = x^3 (1/3x)(3) + ln3x * 3x^2 [Derivative of lnx = 1/x] \n" ); document.write( " = x^2 + 3x^2 ln3x [on simplifying] \n" ); document.write( " = x^2(1 + 3ln3x)\r \n" ); document.write( "\n" ); document.write( "(ii) y = e^ln5x \n" ); document.write( " = 5x [because e^lnx = x only] \n" ); document.write( "dy/dx = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(iii) y = e^lnx \n" ); document.write( " = x \n" ); document.write( "dy/dx = 1\r \n" ); document.write( "\n" ); document.write( "(iv) I believe the question is y = [ln(5x+2)^3]/ln(5x+2)\r \n" ); document.write( "\n" ); document.write( " = 3ln(5x+2)/ln(5x+2) [property of ln] \n" ); document.write( " = 3 \n" ); document.write( "So dy/dx = 0\r \n" ); document.write( "\n" ); document.write( "Good Luck!!! \n" ); document.write( " |