document.write( "Question 649345: A person starts a journey from his home and travels in a speed of 5Km/h he arrives to the destination 1 minute late. and if he travels in a speed of 6Km/h he arrives 1 minute early . what's the distance he traveled? \n" ); document.write( "
Algebra.Com's Answer #407023 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A person starts a journey from his home and travels in a speed of 5Km/h, he arrives to the destination 1 minute late. \n" ); document.write( " and if he travels in a speed of 6Km/h he arrives 1 minute early. \n" ); document.write( " what's the distance he traveled? \n" ); document.write( ": \n" ); document.write( "Let d = the distance traveled \n" ); document.write( ": \n" ); document.write( "The time difference between the two scenarios is 2 min: 2/60 = 1/30 hr \n" ); document.write( ": \n" ); document.write( "Write a time equation: time = dist/speed \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "multiply by 30 \n" ); document.write( "6d - 5d = 1 \n" ); document.write( "d = 1 mi is the distance he traveled \n" ); document.write( " |