document.write( "Question 649593: Among the 2,598,960 possible five-card poker hands from a standard 52-card deck, how many contain AT LEAST ONE CLUB (complement of \"no clubs\")? \n" ); document.write( "
Algebra.Com's Answer #407019 by swincher4391(1107)![]() ![]() You can put this solution on YOUR website! N[at least one club] = N[total ways] - N'[at least one club] = N[total ways] - N[no clubs]\r \n" ); document.write( "\n" ); document.write( "There are 39 cards without a club. So there are 39 choose 5 = 575757 ways to not get a club.\r \n" ); document.write( "\n" ); document.write( "There are 2598960 possible hands, leaving us with 2598960-575757 ways.\r \n" ); document.write( "\n" ); document.write( "Which is 2023203 hands.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |