document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=649550>Question 649550</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find a 4 digit number such that the number formed by reversing the digits is 4 times its original number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #406988 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=406988\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We know that D must be even because 4D = A. A has to be 2 since A*4 + any thing we carry from the hundreds gives a number less than 10. So D could be 8 or 9. D must be 8 because 8*4 ends in 2 and 9*4 does not.\r<BR>\n" );
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document.write( "B*4 gives us a number less than 10 since there is no carry figure to the thousands. B must be different than A, so B must be 1.  We have found that A=2 B = 1 D = 8.  We know that 21C8 * 4 =  8C12. When we take C and multiply it by 4 and add 3 ( since 8*4 = 32) we get 7. Which is C.\r<BR>\n" );
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document.write( "Thus the number is 2178.  </SPAN>\n" );
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