document.write( "Question 649492: A man cycles from his office to his house at a speed of 5 km/hr and reaches 10 minutes late. If he cycles at a speed of 6 km/hr, he reaches 10 minutes early. What is the distance between the office and his house?
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Algebra.Com's Answer #406972 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+d+\" = the distance in km between house and office
\n" ); document.write( "Let \"+t+\" = The travel time in hrs which is on time for him
\n" ); document.write( "given:
\n" ); document.write( "From office to house at 5 km/hr
\n" ); document.write( "(1) \"+d+=+5%2A%28+t+%2B+10%2F60+%29+\"
\n" ); document.write( "From office to house at 6 km/hr
\n" ); document.write( "(2) \"+d+=+6%2A%28+t+-+10%2F60+%29+\"
\n" ); document.write( "-----------------------
\n" ); document.write( "(1) \"+d+=+5t+%2B+5%2F6+\"
\n" ); document.write( "(2) \"+d+=+6t+-+1+\"
\n" ); document.write( "----------------
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+5t+%2B+5%2F6+=+6t+-+1+\"
\n" ); document.write( "(2) \"+t+=+5%2F6+%2B+1+\"
\n" ); document.write( "(2) \"+t+=+11%2F6+\"
\n" ); document.write( "Plug this result back into (1) or (2)
\n" ); document.write( "(1) \"+d+=+5%2A%2811%2F6%29+%2B+5%2F6+\"
\n" ); document.write( "(1) \"+d+=+55%2F6+%2B+5%2F6+\"
\n" ); document.write( "(1) \"+d+=+10+\"
\n" ); document.write( " the distance between his house and office is 10 km
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+d+=+6t+-+1+\"
\n" ); document.write( "(2) \"+10+=+6t+-+1+\"
\n" ); document.write( "(2) \"+6t+=+11+\"
\n" ); document.write( "(2) \"+t+=+11%2F6+\"
\n" ); document.write( "OK
\n" ); document.write( "(1) \"+d+=+5t+%2B+5%2F6+\"
\n" ); document.write( "(1) \"+10+=+5t+%2B+5%2F6+\"
\n" ); document.write( "(1) \"+5t+=+10+-+5%2F6+\"
\n" ); document.write( "(1) \"+5t+=+60%2F6+-+5%2F6+\"
\n" ); document.write( "(1) \"+5t+=+55%2F6+\"
\n" ); document.write( "(1) \"+t+=+11%2F6+\"
\n" ); document.write( "OK\r
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