document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=649046>Question 649046</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The question say \"Angle A and angle B are complementary. If angle A= 3x + 40, and angle B= 2x-10, find the measure of each angle  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #406874 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=406874\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The question say \"Angle A and angle B are complementary. If angle A= 3x + 40, and angle B= 2x-10, find the measure of each angle <BR>\n" );
document.write( "-------<BR>\n" );
document.write( "A + B = 90 degrees<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "3x+40 + 2x-10 = 90<BR>\n" );
document.write( "5x = 60<BR>\n" );
document.write( "x = 12<BR>\n" );
document.write( "------<BR>\n" );
document.write( "A = 3x+40 = 3*12+40 = 76 degrees<BR>\n" );
document.write( "----<BR>\n" );
document.write( "B = 2x-10 = 2*12-10 = = 14 degrees<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=============== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );