document.write( "Question 648986: What is the center and radius of (x-3)^2+(y-1)^2=36? \n" ); document.write( "
Algebra.Com's Answer #406864 by MathLover1(20849)\"\" \"About 
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the general formula of the circle is \"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\" where \"+h\" and \"k\" are the \"x\" and \"y\" coordinates of the \"center\" of the circle , and \"r\" is the \"radius\"\r
\n" ); document.write( "\n" ); document.write( "you are given \"%28x-3%29%5E2%2B%28y-1%29%5E2=36\"\r
\n" ); document.write( "\n" ); document.write( "if you compare your equation to the general formula of the circle, you can see that \"h=3\" and \"k=1\";so, the \"center\" is at (\"3\",\"1\")\r
\n" ); document.write( "\n" ); document.write( "and \"r%5E2=36\"...->... \"r=6\"\r
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Solved by pluggable solver: PLOT any circle and describe it

\n" ); document.write( " Diameter: \"d+=+2r+=+2%2A6+=+12\".
\n" ); document.write( " Area: \"area+=+pi%5Cr%5E2+=+pi%2A6%5E2+=+113.097336983618\"
\n" ); document.write( " Perimeter: \"perimeter+=+2%5Cpi%5Cr+=+2%5Cpi%2A6+=+37.6991123278728\"
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