document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=648824>Question 648824</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Travel by car: Marcus drives from one town to another in 6 hours. On the return trip, his speed increased by 10 mph and the trip takes 5 hours. Find his rate on the return trip. How far apart are the towns? \r<BR>\n" );
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document.write( "So far I know:<BR>\n" );
document.write( "rate x time= distance<BR>\n" );
document.write( "Going trip- rate= r   time =6  distance= ?<BR>\n" );
document.write( "Return trip-  rate= r+10   time= 5  distance=? \r<BR>\n" );
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document.write( "I am not sure how to proceed in writing and solving the equation.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #406862 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10553)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=406862\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Travel by car: Marcus drives from one town to another in 6 hours. On the return trip, his speed increased by 10 mph and the trip takes 5 hours. Find his rate on the return trip. How far apart are the towns? \r<BR>\n" );
document.write( "\n" );
document.write( "So far I know:<BR>\n" );
document.write( "rate x time= distance<BR>\n" );
document.write( "Going trip- rate= r   time =6  distance= ?<BR>\n" );
document.write( "Return trip-  rate= r+10   time= 5  distance=? \r<BR>\n" );
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document.write( "I am not sure how to proceed in writing and solving the equation.\r<BR>\n" );
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document.write( "Let the town he left from be town A and the town he went to, town B<BR>\n" );
document.write( "Let rate of speed from town B to town A, be S<BR>\n" );
document.write( "Then speed from town A to town B = S - 10 \r<BR>\n" );
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document.write( "Distance from town A to town B equals distance from town B to town A, OR \r<BR>\n" );
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document.write( "6(S – 10) = 5S\r<BR>\n" );
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document.write( "6S – 60 = 5S \r<BR>\n" );
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document.write( "6S – 5S = 60 \r<BR>\n" );
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document.write( "S, or speed on return trip (from town B to town A) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2860%29 ALIGN=MIDDLE  ALT=\"highlight_green%2860%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > mph \r<BR>\n" );
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document.write( "Distance between the towns = 6(60 – 10), or 5(60), or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28300%29 ALIGN=MIDDLE  ALT=\"highlight_green%28300%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > miles.\r<BR>\n" );
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document.write( "You can do the check!!\r<BR>\n" );
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document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com  </SPAN>\n" );
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