document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=648870>Question 648870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I would like help on my geometry math problem. It says here that I need to find the measures of two complementary angles if the difference in measure is 18.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #406835 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=406835\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x and y be complementary angles.\r<BR>\n" );
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document.write( "Then  x-y = 18\r<BR>\n" );
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document.write( "y = x+18\r<BR>\n" );
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document.write( "By definition, complementary angles add up to 90.\r<BR>\n" );
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document.write( "x + y = 90\r<BR>\n" );
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document.write( "x + x+18 = 90\r<BR>\n" );
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document.write( "x +x = 72\r<BR>\n" );
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document.write( "2x = 72\r<BR>\n" );
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document.write( "x = 36\r<BR>\n" );
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document.write( "y = 36 + 18\r<BR>\n" );
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document.write( "y = 54\r<BR>\n" );
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document.write( "36,54 </SPAN>\n" );
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