document.write( "Question 59355: Find an equation relating the variables for each situation described.\r
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document.write( "(1) z varies directly as b, and z = 4 when b = 16\r
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document.write( "(2) s2 varies inversely as s1, and s2= -2 when s1 = 1/2\r
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document.write( "(3) y varies jointly as a and b, and y = -24 when a = 9 and b = -4\r
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document.write( "(4) m varies directly as n and inversely as p, and p = -3 and m = 1 and n = 1/2\r
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document.write( "(5) The cost of pipe is directly proportional to its length. If 6 feet of pipe costs $40, find he cost of 10 feet of pipe.\r
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document.write( "(6) The intensity of light is inversely prorportional to the square of its distance from its origin. An intensity of 100 lumens is registered at a distance of 5 feet. What is the intensity of light registered at a distance of 10 feet? \n" );
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Algebra.Com's Answer #40680 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! Find an equation relating the variables for each situation described. \n" ); document.write( ": \n" ); document.write( "(1) z varies directly as b, and z = 4 when b = 16 \n" ); document.write( " \"z varies direclty as b\" -->> z=kb \n" ); document.write( "z=4 and b=16 find k: \n" ); document.write( "4=k(16) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Substitute that into the first step: \n" ); document.write( " \n" ); document.write( ":\r \n" ); document.write( "\n" ); document.write( "(2) s2 varies inversely as s1, and s2= -2 when s1 = 1/2 \n" ); document.write( "\"s2 varies inversely as s1\" -->> s2=k/s1 \n" ); document.write( "s2=-2 and s1=1/2 find k: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Substitute that into the first step: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "(3) y varies jointly as a and b, and y = -24 when a = 9 and b = -4 \n" ); document.write( "\"y varies jointly as a and b\" -->> y=kab \n" ); document.write( "y=-24, a=9, and b=-4, find k \n" ); document.write( "-24=k(9)(-4) \n" ); document.write( "-24=-36k \n" ); document.write( "-24/-36=-36k/-36 \n" ); document.write( "2/3=k \n" ); document.write( "Substitute that into the first step: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "(4) m varies directly as n and inversely as p, and p = -3 and m = 1 and n = 1/2 \n" ); document.write( "\"m varies directly as n and inversely as p\" -->> m=kn/p \n" ); document.write( "p=-3, m=1, and n=1/2 find k \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Substitute that into step 1: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "(5) The cost of pipe is directly proportional to its length. If 6 feet of pipe costs $40, find the cost of 10 feet of pipe. \n" ); document.write( "Let cost be:C and Length be:L \n" ); document.write( "\"cost is directly proportional to length\" -->> C=kL \n" ); document.write( "C=40, L=6, find k: \n" ); document.write( "40=k(6) \n" ); document.write( "40/6=6k/6 \n" ); document.write( "6.667=k \n" ); document.write( "Substitute that into the first step: \n" ); document.write( "Let L=10 \n" ); document.write( "C=(6.667)(10) \n" ); document.write( "C=$66.67 \n" ); document.write( ": \n" ); document.write( "(6) The intensity of light is inversely prorportional to the square of its distance from its origin. An intensity of 100 lumens is registered at a distance of 5 feet. What is the intensity of light registered at a distance of 10 feet? \n" ); document.write( "Let intensity be:I and distance be:d \n" ); document.write( "\"intensity of light in inversely proportional to the square of its distance\" -->> \n" ); document.write( "I=100, d=5, find k \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Substitute that into step 1: \n" ); document.write( " \n" ); document.write( "If d=10 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "I=25 lumens \n" ); document.write( "Happy Calculating!!! \n" ); document.write( " |